for power series

𝑛𝑎𝑛

like the content in Calculus II, do the ratio test

lim𝑛|𝑎𝑛+1𝑎𝑛|

then the radius of convergence is 1𝑁 where 𝑁 is at most what 𝑥 can let it less than 1 (convergence condition).

Example

𝑛=02𝑛𝑥𝑛

So

𝑎𝑛=2𝑛𝑥𝑛

and

𝑎𝑛+1=2𝑥2𝑛𝑥𝑛

then

lim𝑛|𝑎𝑛+1𝑎𝑛|=|2𝑥|

Then we can say the radius of convergence is 𝑅=1𝑁=12.