2. Closure is closed

Let (𝑥𝑛). Show that

𝑆={𝑥𝑛|𝑛}𝐿𝑖𝑚(𝑥𝑛)

is closed. Show that 𝑆 is compact (𝑥𝑛) is bounded.
Firstly, we can prove 𝑆 is closed by contradiction: suppose there exists (𝑥𝑛𝑗)𝑆 such that lim(𝑥𝑛𝑗)𝑆, we have two cases:

  1. If (𝑥𝑛𝑗)(𝑥𝑛), it leads to a contradiction with lim(𝑥𝑛𝑗)𝑆 due to 𝐿𝑖𝑚(𝑥𝑛)𝑆 and lim(𝑥𝑛𝑗)𝐿𝑖𝑚(𝑥𝑛).
  2. If 𝐴=(𝑥𝑛𝑗)\(𝑥𝑛) and lim(𝑥𝑛𝑗)=𝑥, we can say 𝐴𝐿𝑖𝑚(𝑥𝑛) and lim(𝑥𝑛𝑗)=lim(𝐴)𝐿𝑖𝑚(𝑥𝑛) which leads to a contradiction with lim(𝑥𝑛𝑗)𝑆.
    Hence in both cases we can say 𝑆 is closed proved by contradiction.