Eritque Arcus Math Notes
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❯
DifferentialEquation
❯
CH3
❯
variation of parameters
variation of parameters
May 15, 2025
1 min read
y
′
+
p
(
t
)
y
y
′
y
1
(
ln
∣
y
∣
)
′
y
=
0
=
−
p
(
t
)
=
−
p
(
t
)
=
C
e
−
∫
p
(
t
)
d
t
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